Mathematics
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OpenStudy (anonymous):
Help with homework im stuck on it
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OpenStudy (anonymous):
OpenStudy (solomonzelman):
he replaces the card, so the events are not dependent on each other,.
OpenStudy (anonymous):
@SolomonZelman yesss
OpenStudy (solomonzelman):
what is the probability that the first card is club ?
OpenStudy (anonymous):
@SolomonZelman 13/52?
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OpenStudy (solomonzelman):
or, reduces to?
OpenStudy (anonymous):
@SolomonZelman can it be reduced
OpenStudy (solomonzelman):
yes, 52 = 13 * 4
OpenStudy (anonymous):
@SolomonZelman ahhh now i see so 1/4
OpenStudy (solomonzelman):
yes, and what is the probability that the second card is NOT a heart ?
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OpenStudy (anonymous):
@SolomonZelman 26/52
OpenStudy (solomonzelman):
not heart, means any of the remaining suits.
OpenStudy (anonymous):
@SolomonZelman SO 32/52
OpenStudy (anonymous):
@SolomonZelman 39/52
OpenStudy (solomonzelman):
yes, and this can be reduced to?
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OpenStudy (anonymous):
@SolomonZelman 3/4
OpenStudy (solomonzelman):
yes, so you have two events, the probability of 1 is 3/4 and the probability of the other is 1/4.
OpenStudy (anonymous):
@SolomonZelman so multiply them
OpenStudy (solomonzelman):
you need the probability that event A will occur and event B will occur (right after event A)
yes multiply.
OpenStudy (anonymous):
@SolomonZelman ahh ok so 3/16 is the answer
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OpenStudy (solomonzelman):
yup
OpenStudy (anonymous):
@SolomonZelman ty very much for the help and steps