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Mathematics 16 Online
OpenStudy (anonymous):

Help with homework im stuck on it

OpenStudy (anonymous):

OpenStudy (solomonzelman):

he replaces the card, so the events are not dependent on each other,.

OpenStudy (anonymous):

@SolomonZelman yesss

OpenStudy (solomonzelman):

what is the probability that the first card is club ?

OpenStudy (anonymous):

@SolomonZelman 13/52?

OpenStudy (solomonzelman):

or, reduces to?

OpenStudy (anonymous):

@SolomonZelman can it be reduced

OpenStudy (solomonzelman):

yes, 52 = 13 * 4

OpenStudy (anonymous):

@SolomonZelman ahhh now i see so 1/4

OpenStudy (solomonzelman):

yes, and what is the probability that the second card is NOT a heart ?

OpenStudy (anonymous):

@SolomonZelman 26/52

OpenStudy (solomonzelman):

not heart, means any of the remaining suits.

OpenStudy (anonymous):

@SolomonZelman SO 32/52

OpenStudy (anonymous):

@SolomonZelman 39/52

OpenStudy (solomonzelman):

yes, and this can be reduced to?

OpenStudy (anonymous):

@SolomonZelman 3/4

OpenStudy (solomonzelman):

yes, so you have two events, the probability of 1 is 3/4 and the probability of the other is 1/4.

OpenStudy (anonymous):

@SolomonZelman so multiply them

OpenStudy (solomonzelman):

you need the probability that event A will occur and event B will occur (right after event A) yes multiply.

OpenStudy (anonymous):

@SolomonZelman ahh ok so 3/16 is the answer

OpenStudy (solomonzelman):

yup

OpenStudy (anonymous):

@SolomonZelman ty very much for the help and steps

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