Question

Complete the table of values for this circuit. Use KVL and Ohm's Laws.

Answer 1

Can anyone explain how to get at least the first box?

Answer 2

Lets find equivalent resistance of the circuit:
Here R1 is parallel to R2 and they are in series with R3:
\[R_{12}=\frac{R_1R_2}{R_1+R_2}=81.7Ohms\]
\[Req=R_{12}+R_3=551.7Ohms\]

Now we can find current on \[R_3\], that is
\[I_3=\frac{V}{Req}=\frac{12V}{551.7}=0.022A\]
\[V_3=I_3R_3=0.022*470=10.22V\]
Voltage is split in series, so voltage on R1 and R2 are equal
\[V_1=V_2=V-V_3=12-10.22=1.78V\]
Now you can find current on R1 and R2, from V2/R2 and V1/R1