Question

3^-3

Answer 1

\[a^{-b} = \frac{ 1 }{ a^{+b} }\]

Answer 2

\[\large x^{-n} \implies \frac{ 1 }{ x^n }\]

Answer 3

i dont understand

Answer 4

move the base 3 to the other side of the fraction, and change the sign on the power

Answer 5

1 / 3^3

Answer 6

also in the denominator with 1 on the numerator and the denominator will be raised to the 3rd power

Answer 7

\[\frac{ 3^{-3} }{ 1 } = \frac{ 1 }{ 3^3 }\]

Answer 8

so it would be -1/27 ?

Answer 9

no

Answer 10

\[\frac{ 3^{-3} }{ 1 } = \frac{ 1 }{ 3^3 } = \frac{ 1 }{ 27 }\]

Answer 11

-27 by it self?

Answer 12

one twenty seventh

Answer 13

so just take away the negative sign

Answer 14

you can move bases raised to powers to the other side of the fraction, and that will change the sign on the power.
\[3^{-3} = \frac{ 1 }{ 3^3 } = \frac{ 1 }{ 27 }\]

Answer 15

try
\[\frac{ 3^{-10 }}{ 5^{-4} } = \]

Answer 16

sorry got to run... change the sign on the power when you change the side of the fraction the base is on...like this..

\[\frac{ 3^{-10 }}{ 5^{-4} } = \frac{ 5^4 }{ 3^{10} }\]