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Mathematics 19 Online
OpenStudy (anonymous):

What does the slope of a Force of Friction vs Weight graph represent?

OpenStudy (anonymous):

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OpenStudy (anonymous):

@UnkleRhaukus

OpenStudy (unklerhaukus):

|dw:1421715713990:dw|

OpenStudy (anonymous):

yes

OpenStudy (unklerhaukus):

Where the weight is \(W =mg\), the normal force is \(N = W\cos\theta=mg\cos\theta\), the friction force is \(f = \mu N=\mu mg\cos\theta\), and the net force is \(F= W\sin \theta = mg\sin\theta\)

OpenStudy (unklerhaukus):

The friction force, in-terms of weight will be \[f=\mu W\cos\theta\]

OpenStudy (anonymous):

|dw:1421716469598:dw|

OpenStudy (anonymous):

so does the slope represent = mu cos theta?

OpenStudy (unklerhaukus):

yep

OpenStudy (anonymous):

does mu cos theta mean anything in physics?

OpenStudy (unklerhaukus):

the coefficient of friction is also\[\mu =\tan\theta\]

OpenStudy (anonymous):

how so?

OpenStudy (unklerhaukus):

so the slope \(\mu\cos\theta\) becomes \[\tan\theta\cos\theta=\]

OpenStudy (anonymous):

how is mu = tan theta?

OpenStudy (unklerhaukus):

i think it is just a definition

OpenStudy (unklerhaukus):

use tan = sin /cos

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