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What does the slope of a Force of Friction vs Weight graph represent?
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|dw:1421715002547:dw|
@UnkleRhaukus
|dw:1421715713990:dw|
yes
Where the weight is \(W =mg\), the normal force is \(N = W\cos\theta=mg\cos\theta\), the friction force is \(f = \mu N=\mu mg\cos\theta\), and the net force is \(F= W\sin \theta = mg\sin\theta\)
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The friction force, in-terms of weight will be \[f=\mu W\cos\theta\]
|dw:1421716469598:dw|
so does the slope represent = mu cos theta?
yep
does mu cos theta mean anything in physics?
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the coefficient of friction is also\[\mu =\tan\theta\]
how so?
so the slope \(\mu\cos\theta\) becomes \[\tan\theta\cos\theta=\]
how is mu = tan theta?
i think it is just a definition
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use tan = sin /cos
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