Question

help?
What is true about the solutions of a quadratic equation when the radicand of the quadratic formula is zero?
No real solutions
Two identical rational solutions
Two different rational solutions
Two irrational solutions

Answer 1

\[ax^2+bx+c=0 \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
so when b^2-4ac=0
we have
\[x=\frac{-b \pm \sqrt{0}}{2a}= \frac{-b \pm 0 }{2a}=\frac{-b}{2a}\]

Answer 2

so what do you think that means

Answer 3

its the last one

Answer 4

@zachleestone check again
rational means can be expressed as a ratio of 2 integers
irrational means not with integers

Answer 5

ok.i see