Given b = 12, c = 15 and A = 60° in triangle ABC, use the Law of Cosines to solve for a. Fill in the blank(s) to complete each step. Round your answer to the nearest hundredth.
a2 = --- + 152 - 2 --- (15) cos ---°
a2 = 144 + 225 - 360(---)
a2 = ---
a = ---
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OpenStudy (anonymous):
@zachleestone
OpenStudy (anonymous):
i have to fill the --- up
OpenStudy (perl):
|dw:1421737247842:dw|
OpenStudy (perl):
You can use the equation
b^2 + c^2 - 2b*c*cos(60) = a^2
OpenStudy (anonymous):
a = 16.82 right? @perl
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OpenStudy (perl):
not quite
OpenStudy (anonymous):
im just bad at these stuff:(
OpenStudy (anonymous):
357?
OpenStudy (perl):
that was a typo
OpenStudy (anonymous):
u mean?
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OpenStudy (perl):
I left out 15 , but i fixed it
OpenStudy (anonymous):
oh what about a?
OpenStudy (perl):
If we substitute
b = 12
c = 15
theta = 60 degrees
into the equation
b^2 + c^2 - 2ab cos (theta) = a^2
12^2 + 15^2 - 2*12*15cos(60 degrees) = a^2
144 + 225 - 2*12*15*1/2 = a^2
144 + 225 - 360*cos(60) = a^2
144 + 225 - 360 *1/2 = a^2
369 - 180 = a^2
189 = a^2