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Find how many different 4-digit numbers can be formed from the digits 1, 3, 5, 6, 8 and 9 if each digit may be used only once. ii/ Find how many of these 4-digit numbers are even
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You mean... if I will form a 4-digit numbers... I will never use the 4-digit numbers that I've use on the next 4-digit numbers I will form?
so basically it's a permutation/combination qus. if i already have 360 chances of getting a 4-digit number, how many chances will i have of getting a 4-digit number which is even
we have 6 different digits, and four locations to put them
how many different numbers can we put in the first place? how many in the second? how many in the third? how many in the fourth?
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