Given S=n/2(n+1) Complete the ordered pair. D = {(n, S): (0, __)
given \[S=\frac{ n }{ 2 }(n+1)\]
you're given that n=0 so just plug in the value "0" into the given formula to get S
the ordered pair consists of (n,S) right?
I guess I am so confused with the lesson I am in I have read it over and over and it just doesn't make since to me
well the ordered pair consists of two numbers for x and y as in "(x,y)"... in this case you have an ordered pair of (n,S) and you're given the value of n=0 as well as the formulas for the S value, just plug in "n" to find "S" :)
plug in n=0 in the given? so like S=0/2(0+1) so it would 1 or did u mean something different
that's what I meant, so you should get 0 and your ordered pair will be (0,0)
okay thank you :)
np :)
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