Question

what are the zeroes of the fuction?
x(squared)-2x+5=0
Fan and medal!

Answer 1

you could use the quadratic formula

Answer 2

ok

Answer 3

\[ax^2+bx+c=0 \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
steps: identify and plug in and evaluate

Answer 4

\[x=\div2\pm \sqrt{-2^2-4(1)(5)}\]

Answer 5

over 2(1)

Answer 6

@freckles I got \[x=2\pm \sqrt{16}\div2\]

Answer 7

\[x=\frac{-(-2) \pm \sqrt{(-2)^2-4(1)(5)}}{2(1)}=\frac{2 \pm \sqrt{4-20}}{2}=\frac{2 \pm \sqrt{-16}}{2}\]
close

Answer 8

this can be simplified though