E.J. has shown that a function, f(x), grows by 12% for every unit in the domain. What does this prove? The function f(x) is an arithmetic sequence. The function f(x) is a geometric sequence. The function f(x) is not a sequence. This does not prove anything.
@Miracrown
To solve it, first we need to know what's the problem telling us. let's say f(0)=a
so, what do we get for f(1)?
please note that f(x) increases 12% for each unit
We need to know what does 12% represents 12% is 0.12 written in decimal numbers Right? So, if we're increasing 12% the previous value, how do you think we can write it?
0<x<.12 ? @Miracrown sorry my connection was a little bad and f(1)=.12 f(2)=.24 etc.
@DanJS
http://www.differencebetween.com/difference-between-arithmetic-sequence-and-vs-geometric-sequence/
look at the part about geometric sequences
y = A*r^x when 0 < r < 1 exponential decay
A geometric sequence is defined as a sequence in which the quotient of any two consecutive terms is a constant.
If the next term is always 12 percent larger than the previous. It will fall under that definition
If you divide the (n+1)th term by the nth term, you will get a constant
so its a geometric sequence (the 3rd one?) @DanJS
geometric , yes
growing "geometrically" (or "exponentially")
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