Question

x^2-2x+3=0.. how many real solutions?

Answer 1

hmm

Answer 2

infinitely many solutions

Answer 3

False

Answer 4

?

Answer 5

That's not true

Answer 6

:/

Answer 7

then one solution if my answer isn't true

Answer 8

but my answer is true

Answer 9

Use the discriminant D = b^2 - 4ac

Answer 10

it's infinitely many solutions simple algebra bro

Answer 11

\[\frac{ -b \pm \sqrt{b ^{2}-4ac} }{2a}\]
ax^2+bx+c
a=1, b=-2, c=3

Answer 12

there r infinitely many solutions

Answer 13

That's not even a possibility

Answer 14

Is it 2 @AJ01?

Answer 15

sorry i was a way...\[\frac{ -(-2)\pm \sqrt{(-2)^{2}-4*1*2} }{ 1*2 }\]

Answer 16

\[\frac{ 2\pm \sqrt{4-12} }{ 2 }=1\pm \frac{ \sqrt{-8} }{ 2}=1\pm \frac{ \sqrt{4*-2} }{ 2}\]

Answer 17

\[1\pm \sqrt{-2}\]

Answer 18

AJ01, you plugged in c = 2 when it should be c = 3

Answer 19

thanks but the multiplication is 3*4=12 just miss typing