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OpenStudy (anonymous):
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OpenStudy (anonymous):
\[2^{2x}-2^{x+1}-15=0\]
OpenStudy (anonymous):
@ganeshie8 @triciaal
OpenStudy (anonymous):
@Hero @Kainui
OpenStudy (triciaal):
one approach
put the number to the right
take the logs of each side
OpenStudy (anonymous):
what number goes to the right?
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OpenStudy (triciaal):
when you subtract logs you divide the numbers
OpenStudy (anonymous):
I know but you said to put the number on the right. What number is that? the 2^2x? 2^x-1?15?
OpenStudy (triciaal):
constant 15
OpenStudy (triciaal):
isolating the x
OpenStudy (triciaal):
using base 2
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OpenStudy (triciaal):
@Nnesha can you help?
OpenStudy (anonymous):
sorry can u draw it out? I know its a lot to ask for
OpenStudy (triciaal):
@ganeshie8 please help
OpenStudy (triciaal):
@UnkleRhaukus please help
OpenStudy (unklerhaukus):
\[2^{2x}-2^{x+1}-15=0\\
2^{2x}-2^{x+1}=15\\2^x(2^x-2)=15\]
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OpenStudy (anonymous):
then what?
OpenStudy (unklerhaukus):
i'm not sure i got stuck
Nnesha (nnesha):
need wrong answer ??
tell me so i can try :(
OpenStudy (anonymous):
Tell you what?
Nnesha (nnesha):
nvm nothing :)
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Nnesha (nnesha):
idk how u got
2^x(2^x -2) ??
Nnesha (nnesha):
you should move |dw:1421911840284:dw|
this -2 to other side then its become positive then you can take log
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