I NEED VOLUME HELP!!!!!
In this problem we will find the volume of a solid with circular base of radius 8, for which parallel cross-sections perpendicular to the base are squares. To do this, we will assume that the base is the circle x^2 + y^2 = 8^2, so that the solid lies between planes parallel to the x-axis at x=8 and x=-8 The cross-sections perpendicular to the x-axis are then squares whose bases run from the semicircle y=-sqrt{64-x^2}to the semicircle y=sqrt{64-x^2} What is the area of the cross-section at x ? A(x)= What is the volume of the solid ? displaystyle V=
holy crap. umm, can you add some correct grammar to this so it makes it easier for me to divide all of this in my head?
Such as periods and commas
I'm not trying to be rude i just need to divide the problem up into groups in my head.
This was copied (Ctrl-C) directly from my homework site. Give me a second
k12?
No, Webwork. College homework program
Nice. I'm doing some of k12's college programs.
To do this, we will assume that the base is the circle \[x ^{2}+y ^{2}=8^{2}\], so that the solid lies between planes parallel to the x-axis at x=8 and x=-8. The cross-sections perpendicular to the x-axis are then squares whose bases run from the semicircle y=-sqrt{64-x^2}to the semicircle y=sqrt{64-x^2}. What is the area of the cross-section at I added all the commas and periods that was lost from coping the problem
thanks this makes it much easier
openstudy needs to revise their HTML. can isend it to you via PM?
it won't let me post myimage
alright that'll be fine. thanks
I have sent you the circle
I see it.
ok so now we have the next equation
the integer solution should be \[x= \pm8 y=0\]
sorry for the lack of a space between the 8 and the y
its fine
whoops! and stands for y
can you take it from here i have to go and finish my schoolwork for the day xD
I should be able too. Good luck
thanks mate! i'll fan you and medal you! (it'd be awesome if you could do the same)
Join our real-time social learning platform and learn together with your friends!