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Mathematics 19 Online
OpenStudy (anonymous):

I NEED VOLUME HELP!!!!!

OpenStudy (anonymous):

In this problem we will find the volume of a solid with circular base of radius 8, for which parallel cross-sections perpendicular to the base are squares. To do this, we will assume that the base is the circle x^2 + y^2 = 8^2, so that the solid lies between planes parallel to the x-axis at x=8 and x=-8 The cross-sections perpendicular to the x-axis are then squares whose bases run from the semicircle y=-sqrt{64-x^2}to the semicircle y=sqrt{64-x^2} What is the area of the cross-section at x ? A(x)= What is the volume of the solid ? displaystyle V=

OpenStudy (jacobbirddog):

holy crap. umm, can you add some correct grammar to this so it makes it easier for me to divide all of this in my head?

OpenStudy (jacobbirddog):

Such as periods and commas

OpenStudy (jacobbirddog):

I'm not trying to be rude i just need to divide the problem up into groups in my head.

OpenStudy (anonymous):

This was copied (Ctrl-C) directly from my homework site. Give me a second

OpenStudy (jacobbirddog):

k12?

OpenStudy (anonymous):

No, Webwork. College homework program

OpenStudy (jacobbirddog):

Nice. I'm doing some of k12's college programs.

OpenStudy (anonymous):

To do this, we will assume that the base is the circle \[x ^{2}+y ^{2}=8^{2}\], so that the solid lies between planes parallel to the x-axis at x=8 and x=-8. The cross-sections perpendicular to the x-axis are then squares whose bases run from the semicircle y=-sqrt{64-x^2}to the semicircle y=sqrt{64-x^2}. What is the area of the cross-section at I added all the commas and periods that was lost from coping the problem

OpenStudy (jacobbirddog):

thanks this makes it much easier

OpenStudy (jacobbirddog):

openstudy needs to revise their HTML. can isend it to you via PM?

OpenStudy (jacobbirddog):

it won't let me post myimage

OpenStudy (anonymous):

alright that'll be fine. thanks

OpenStudy (jacobbirddog):

I have sent you the circle

OpenStudy (anonymous):

I see it.

OpenStudy (jacobbirddog):

ok so now we have the next equation

OpenStudy (jacobbirddog):

the integer solution should be \[x= \pm8 y=0\]

OpenStudy (jacobbirddog):

sorry for the lack of a space between the 8 and the y

OpenStudy (anonymous):

its fine

OpenStudy (jacobbirddog):

whoops! and stands for y

OpenStudy (jacobbirddog):

can you take it from here i have to go and finish my schoolwork for the day xD

OpenStudy (anonymous):

I should be able too. Good luck

OpenStudy (jacobbirddog):

thanks mate! i'll fan you and medal you! (it'd be awesome if you could do the same)

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