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PLEASE HELP!! Given that f(x) = x2 − 4x − 3 and g(x) = the quantity of x plus three, over four , solve for f(g(x)) when x = 9.
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\((f(\color{red}{x})=\color{red}{x}^2-4\color{red}{x}-3\\(f(\color{red}{g(x)})=\color{red}{(g(x))}^2-4\color{red}{g(x)}-3\) Hence, just replace where you see x by g(x) to get f(g(x) first, then plug x =9 in
im still a bit confused, where would I plug in x=9?
Read my guidance: find f(g(x) FIRST
I don't know how to
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