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Calculus question! Find the limit as x approaches infinity
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\[1/\sqrt{x}\int\limits_{1}^{x}dt/\sqrt{t}\]
Can you solve the integral? You should rewrite t with an exponent instead to help.
\[\frac{ 2 }{ 3}t ^{\frac{ 3 }{ 2 }}\]
Ahhh not quite, that would the integral if the question was \[\large \int\limits \sqrt{t}dt\] but this is slightly different. =)
oops.. lol\[2t ^{\frac{ 1 }{ 2 }}dt\]
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Well almost, after you integrate it the 'dt' part goes away and now you have to evaluate it at the end points, x and 1.
\[2x ^{^{\frac{ 1 }{ 2 }}}-2\]
all over sqrtx right?
Well almost, after you integrate it the 'dt' part goes away and now you have to evaluate it at the end points, x and 1.
is the final answer 2?
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