use the disk method to find the volume of the solid formed by revolving the region bounded by the graph of y=x^3, the y-axis and the lines y=1 and y=8 about the y-axis
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OpenStudy (el_arrow):
i dont know how to do this problem can you help please
OpenStudy (anonymous):
Start by taking
\[
dV= \pi x^2 dy
\]
OpenStudy (anonymous):
\[
y= x^3\\
dy = 3 x^2 dx
\]
OpenStudy (el_arrow):
okay but why a 2 its x^3
OpenStudy (anonymous):
x is the radius of the disk
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OpenStudy (anonymous):
\[
dV= \pi x^2 ( 3 x^2 dx)= 3 \pi x^4 dx
\]
OpenStudy (anonymous):
\[
V= \int_1^2 3 \pi x^4 dx
\]
Compute the integral and you are done
OpenStudy (el_arrow):
where do you get the 2 and 1? you dont use the y=1 and y=8?
OpenStudy (anonymous):
if y=1, then x=1
if \( y = x^3=8 \) then x =2
OpenStudy (el_arrow):
oh okay i see
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OpenStudy (el_arrow):
thank you
OpenStudy (anonymous):
YW
OpenStudy (anonymous):
@eliassaab where did you get that theory from? About the dV=pi*x^2*dy?
OpenStudy (anonymous):
What is the volume of a disk of radius x and thickness dy?
OpenStudy (anonymous):
@doulikepiecauseidont
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