If the point P(-3/5, y)lies on the unit circle and P is the third quadrant, what does y equal?
@misty1212 @jim_thompson5910
P lies on the unit circle, so we know that x^2 + y^2 = 1
x = -3/5 is given to you use this to find y
P is the quadrant 3, so y will be negative
does all that make sense? or no?
so far yes
so you need to solve for y \[\Large x^2 + y^2 = 1\] \[\Large \left(\frac{-3}{5}\right)^2 + y^2 = 1\] \[\Large \frac{9}{25} + y^2 = 1\] \[\Large y = ???\]
I got 4/5 and -4/5
HI!!
hi!
what is the most famous right triangle of all time?
45 45 90?
lol those are angles silly i meant the one with the nice integer sides
y = -4/5 is your answer because remember P is in quadrant 3
y is negative in quadrant 3
|dw:1422238684351:dw|
divide everything by \(5\) and you get this |dw:1422238741718:dw|
since your first coordinate was \(\frac{3}{5}\) the second one had to be \(\frac{4}{5}\) or maybe \(-\frac{4}{5}\) depending on the quadrant
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