Question

The ASCII code used by most computers uses the last seven positions of an eight-bit byte to represent all the characters on a standard keyboard. how many different orderings of 0's and 1's (or how many different characters) can be made by using the last seven positions of an eight-bit byte?

Answer 1

each bit can be 0, or 1, which is one of two possibilities,

Answer 2

so n bits will have 2^n different orderings

Answer 3

Ok

Answer 4

What orderings can it have?

Answer 5

if you only had one bit to work with, there would be 2^1 = 2 possible orderings,
that are 0, 1

if you had two bits there would be 2^2, possible orderings
namely 00, 01, 10, 11

Answer 6

how many bits do you have to work with?

Answer 7

The questions says the bits

Answer 8

how many?

Answer 9

read the question carefully

Answer 10

The bits is 0, and 1

Answer 11

How many bits does the ASCII code use to specify characters?

Answer 12

8

Answer 13

close

Answer 14

7 positions?

Answer 15

yes, so how many possible orderings are there?

Answer 16

14?

Answer 17

@UnkleRhaukus

Answer 18

2^7