What is the quotient (5-x)/(x^2+3x-4) divided by (x^2-2x-15)/(x^2+5x+4) in simplified form? State any restrictions on the variable
\[\frac{ 5-x }{ x^{2} +3x-4}\div \frac{ x^{2}-2x-15 }{ x^{2}+5x+4 }\]
Factorise the quadratic expressions. Change the division sign to multiplication by taking reciprocal of the 2nd part of equation. See if things cancel out
Uh, what? Could you pretty please break it down really simple?
-(x-5)/ (x + 4) ( x - 1) * (x + 4) ( x + 1)/ (x - 5) ( x + 3) (x+4) out and (x - 5) out -(x+1)/(x+3)(x-1) Mathes on pc = hell
okay. Can you factorise all the quadratic expressions?
@TrojanPoem tell him/her how to do it. Not the answer...
I thought , if he saw it answered , he would understand how it's done.
*she And I would like to have the process rather than just the answer, thank you though.
@TrojanPoem Can you help me with more?
Of course.
Solve the complex fraction x/x+3/1/x+1/x+3
sorry that looks bad, I hate using the equation gadget on here
okay Maggie. So we factorise quadratic expressions likes this. \[x ^{2}+3x-4\] You have to break the middle term in such a way that it adds up to get 3x again, but the broken parts multiply to give \[x ^{2} \times -4\]
x/x+3/1/x+1/x+3 Looks horrible that way LOL
Use the EQN and I will try to make you solve it not me.
So it means I have to break my middle term to get \[-4x ^{2}\]. My middle term's 3x. I can break it into 4x - x This will add up to give 3x again, but will multiply to give -4x^2 Now you let the broken part be as it is and factorise by taking something common
a sec
If you want to simplify it just * (x)(x+3) and It will be (x^2) / (2x+3)
Thanks! I may need more help, will you be online for a while?
Not so long , like 10 min more.
Okay, well thanks for your help!
But did you understand how to solve it ?
yes!
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