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Mathematics 25 Online
OpenStudy (anonymous):

what is the magnitude of the vector with an initial point (-3 -2) and terminal point (5 -8)

OpenStudy (thomas5267):

What is the vector first of all?

OpenStudy (anonymous):

I don't know

OpenStudy (anonymous):

@thomas5267

OpenStudy (thomas5267):

Vector are produced by subtracting the coordinates of final point by the coordinate of initial point. In this case, the vector required is (8,-6).

OpenStudy (anonymous):

@ChasingMaggie get it so far?

OpenStudy (anonymous):

Yeah, I'm pretty sure. So after you know what the vector is, what do you have to do?

OpenStudy (anonymous):

find the magnitude, the magnitude for a vector with x and y components is the sqrt((x-component)^2 + (y-component)^2)

OpenStudy (anonymous):

Which one is the x and y components? Is -3 x and -2 y?

OpenStudy (anonymous):

Sorry, I suck at understanding this stuff!

OpenStudy (anonymous):

the vector is (8, -6) so tell me what the x component and y component of the vector would be

OpenStudy (anonymous):

so x component is 8 and y component is -6, right?

OpenStudy (anonymous):

correct :)

OpenStudy (anonymous):

So it would be sqrt8^2+sqrt-6^2?

OpenStudy (anonymous):

no the sqrt is in parenthesis, try again

OpenStudy (anonymous):

sqrt(5 + 2) is not same as sqrt(5) + sqrt(2)

OpenStudy (anonymous):

thats just an example, the numbers dont apply to this problem

OpenStudy (anonymous):

So I find 8^2 and -6^2, then add them, then sqrt that? Or is that all mixed up, too?

OpenStudy (anonymous):

that will work but you want (-6)^2 not -6^2, since (-6)^2 is 36 and -6^2 is -36

OpenStudy (anonymous):

so basically take sqrt(64 + 36)

OpenStudy (anonymous):

So it's 10?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

Because you have to add what's in the parenthesis first, then sqrt it!

OpenStudy (anonymous):

correct :)

OpenStudy (anonymous):

Thank you!

OpenStudy (anonymous):

its really all under the same sqrt symbol but when typing without latex you just use parenthesis to denote that

OpenStudy (anonymous):

yw :)

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