what is the magnitude of the vector with an initial point (-3 -2) and terminal point (5 -8)
What is the vector first of all?
I don't know
@thomas5267
Vector are produced by subtracting the coordinates of final point by the coordinate of initial point. In this case, the vector required is (8,-6).
@ChasingMaggie get it so far?
Yeah, I'm pretty sure. So after you know what the vector is, what do you have to do?
find the magnitude, the magnitude for a vector with x and y components is the sqrt((x-component)^2 + (y-component)^2)
Which one is the x and y components? Is -3 x and -2 y?
Sorry, I suck at understanding this stuff!
the vector is (8, -6) so tell me what the x component and y component of the vector would be
so x component is 8 and y component is -6, right?
correct :)
So it would be sqrt8^2+sqrt-6^2?
no the sqrt is in parenthesis, try again
sqrt(5 + 2) is not same as sqrt(5) + sqrt(2)
thats just an example, the numbers dont apply to this problem
So I find 8^2 and -6^2, then add them, then sqrt that? Or is that all mixed up, too?
that will work but you want (-6)^2 not -6^2, since (-6)^2 is 36 and -6^2 is -36
so basically take sqrt(64 + 36)
So it's 10?
yep
Because you have to add what's in the parenthesis first, then sqrt it!
correct :)
Thank you!
its really all under the same sqrt symbol but when typing without latex you just use parenthesis to denote that
yw :)
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