Question

will medal polynomials

Answer 1

can u use synthetic division when multiplying a polynomial by a polynomial or does it have to b a polynomial by a monomial

Answer 2

@iGreen

Answer 3

hmm, synthetic is just an orginazation of the data. so id assume there is a reasonable way to approach it.

whatever zeroes out the ... whats the bottom called, a divisor?

Answer 4

might help if there is an example that we can test out :)

Answer 5

youre either typing, or one of us is frozen ...

Answer 6

okay well the reson why im asking is because i am having difficulty solving the problems the other ways but synthetic seems to be a better solution for me. but i noticed in class that whenever i used synthetic form it was always when i was multiplying a polynomial by a monomial but i was never told that u cant use it when doin a polynomial by a polynomial.

putting example up in a sec

Answer 7

(im really slow lol)

Answer 8

:) at least its working

Answer 9

a little background info that comes to mind

when we usually do synthetic, we find a value that zeros out the bottom and work the top with it. another thought is if the bottom can be factored then we can always decompose it into parts

Answer 10

okay at this point im just confusing my self i have no idea how to do any of this

Answer 11

so i will just give a problem and maybe u can walk me through it?

Answer 12

\[(2x ^{2}+12x+16) \div (x+2) \]

Answer 13

@amistre64

Answer 14

when does x+2 = 0?

Answer 15

that part i do understand lol that would b x=-2

(so were doing synthetic form? I've discovered i understand that better then the other methods but still not well)

Answer 16

now synthetic is about organizing the data, and there is a textbook way and a better way :)

Answer 17

okay

Answer 18

the better way, is to simply write out the top part as is:

2x^2 +12x +16

now the row beneath it is an adder on row that starts with 0

2x^2 +12x +16
0

now we place the line that seperates the answer from the rest of it

2x^2 +12x +16
0
----------------
|

and in the front of the last row we place that zero

2x^2 +12x +16
0
----------------
-2|

then once we add down we multiply across to get the next adder

Answer 19

let me know if that makes sense

Answer 20

the textbooks say to strip the xs, and place the zero multiplier in front of the top row etc .. that just makes alot of extra work to me

Answer 21

the process is the same, add down, mutliply across

2x^2 +12x +16
0 -4 -16
----------------
-2| 2 8 0


so 2x+8 is the results

Answer 22

it sorta makes sense but not enough for me to actually understand it. I feel like understanding it is right in front of me but still out of my reach like a "its on the tip of my tongue" sorta feeling

Answer 23

2+0 = 2, -2*2 = -4

12-4 = 8, -2*8=-16

16-16=0, and that ends the row as our remainder

Answer 24

okay i think i got the anwser is it

-2x-8 ????

Answer 25

2x+8

Answer 26

(x+2) (2x+8) = 2x^2 + 12x +16

Answer 27

okay i think i know what i did wrong lol

Answer 28

okay im gonna open a new question because i understand it better but not enough to get through the practice problems by myself so im gonna open a new question and tag u in it! thanks so much

Answer 29

:) as long as we learn from out mistakes all is well

if the textbook way to organize the data is better for you, then use it by all means.

i just perfer my own system, i feel its just less effort overall.