Question

the tens digit is six less than the units digit of a two-digit number. When the digits are reversed, the sum of the original and reversed numbers is 132. What is the original number

Answer 1

HI!!

Answer 2

we can do this for sure

Answer 3

ok

Answer 4

lets call the ten digit number \(a\) and that makes the units digit number \(a-6\) so the number itself is
\[10a+a-6\]

Answer 5

like for example if the tens digit was 9, the ones digit would have to be 3 and the number would be \[93=90\times 10+9-6\]

Answer 6

when we reverse them the sum is 132
i have a better idea, instead of doing algebra, lets just check what works
how about \(93+39\) what does that add to?

Answer 7

lol got it on the first try !!

Answer 8

132