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How many squires are there ;)
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count top row count column row multiply the numbers
:O hehe take all properties xD
I'm too lazy to count the squares, and assuming the whole overall shape is a square and not a rectangle, then the answer is: \[\Large \frac{n(n+1)(2n+1)}{6}\]
hahahaha x'd
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but I want to find the general result when the large thingy is an n x m rectangle, so I'm still trying to find a more general answer...!
sow how did you know that its the squires series ?
i just found it and thought its cool to share :O
General form! for m>n rectangle: \[\Large (m-n)\frac{n(n+1)(2n+1)}{6}\]
interesting
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I just started with a small case and worked my way up knowing smaller ones would form larger ones like this: |dw:1422329179535:dw|
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