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Mathematics 16 Online
OpenStudy (anonymous):

How many squires are there ;)

OpenStudy (anonymous):

OpenStudy (anonymous):

count top row count column row multiply the numbers

OpenStudy (anonymous):

:O hehe take all properties xD

OpenStudy (kainui):

I'm too lazy to count the squares, and assuming the whole overall shape is a square and not a rectangle, then the answer is: \[\Large \frac{n(n+1)(2n+1)}{6}\]

OpenStudy (anonymous):

hahahaha x'd

OpenStudy (kainui):

but I want to find the general result when the large thingy is an n x m rectangle, so I'm still trying to find a more general answer...!

OpenStudy (anonymous):

sow how did you know that its the squires series ?

OpenStudy (anonymous):

i just found it and thought its cool to share :O

OpenStudy (kainui):

General form! for m>n rectangle: \[\Large (m-n)\frac{n(n+1)(2n+1)}{6}\]

OpenStudy (anonymous):

interesting

OpenStudy (kainui):

I just started with a small case and worked my way up knowing smaller ones would form larger ones like this: |dw:1422329179535:dw|

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