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OpenStudy (anonymous):
\[3^{5}\sqrt{(x+2)^{3}}+3=27\]
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
is that 5 for the 3? or is it for the root?
OpenStudy (anonymous):
I have no idea... let me screen shot it and post.
jimthompson5910 (jim_thompson5910):
alright
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OpenStudy (anonymous):
Never mind it wont let me screen shot it. its posted all together though.
jimthompson5910 (jim_thompson5910):
the thing is that I wonder if it is
\[\Large 3\sqrt[5]{(x+2)^{3}}+3=27\]
notice how the 5 is the index for the radical
OpenStudy (anonymous):
I think its supposed to be in the index, because thats how it is in the book, and they talked about the index in our last lesson.
jimthompson5910 (jim_thompson5910):
ok so first thing you do is subtract 3 from both sides
OpenStudy (anonymous):
from every number?
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jimthompson5910 (jim_thompson5910):
like this
\[\Large 3\sqrt[5]{(x+2)^{3}}+3=27\]
\[\Large 3\sqrt[5]{(x+2)^{3}}+3{\color{red}{-3}}=27{\color{red}{-3}}\]
\[\Large 3\sqrt[5]{(x+2)^{3}}+0=24\]
\[\Large 3\sqrt[5]{(x+2)^{3}}=24\]
OpenStudy (anonymous):
Oh okay! Thats easy!
OpenStudy (anonymous):
Now what?
jimthompson5910 (jim_thompson5910):
now we divide both sides by 3 to move that "3" on the left side (outside the radical) to the right side
OpenStudy (anonymous):
Now divide by 3 on both sides. Then you have both sides to the power of 5.
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