Another pythagorean theorem problem.

Question

anonymous · Answer

attachment

igreen · Answer

These are the two legs..so we have:

$7^2 + 7^2 = c^2$

Solve for c.

anonymous · Answer

another 
$$a^2+b^2=c^2\
7^2+7^2=c^2$$

anonymous · Answer

try it and see what you get

igreen · Answer

^^^^^^^^^^^^^^^^^^^^^^^^

anonymous · Answer

49 + 49 = c^2

But then it'd be 49 - 49, leaving 0? Or did I go off track?

anonymous · Answer

^^^^^^^

igreen · Answer

49 + 49

igreen · Answer

Not 49 - 49

anonymous · Answer

98 then.

igreen · Answer

Yes, now find the square root of 98.

anonymous · Answer

It comes out uneven, at 9.8 I assume you'd round it up to 10?

igreen · Answer

Yes, that's what I was assuming also..

anonymous · Answer

Hmm, it says 10 was wrong. I guess they wanted it to be rounded down.

anonymous · Answer

wow did they really say ten!!!

anonymous · Answer

no, they wanted you  to day "none of these"

anonymous · Answer

because $98\neq 100$ and so $\sqrt{98}\neq 10$

anonymous · Answer

Ah, yeah that makes sense now actually.

igreen · Answer

Ohhh..

igreen · Answer

The question could've been more specific..like 'don't round your answer'

igreen · Answer

Now you know that you're not supposed to round..lol

anonymous · Answer

Yeah they're not very good at that stuff lol. I'll just redo it later.

anonymous · Answer

i hope no one thinks that 98 = 100
if you do, lend me $100 today, i will pay you back $98 tomorrow and we can call it even

igreen · Answer

Cool, you're a master :P

igreen · Answer

Yes, we know..lol. @satellite73

igreen · Answer

It's just that, I'm used to rounding :P