Question

Another pythagorean theorem problem.

Answer 1

These are the two legs..so we have:

\(7^2 + 7^2 = c^2\)

Solve for c.

Answer 2

another
\[a^2+b^2=c^2\\
7^2+7^2=c^2\]

Answer 3

try it and see what you get

Answer 4

^^^^^^^^^^^^^^^^^^^^^^^^

Answer 5

49 + 49 = c^2

But then it'd be 49 - 49, leaving 0? Or did I go off track?

Answer 6

^^^^^^^

Answer 7

49 + 49

Answer 8

Not 49 - 49

Answer 9

98 then.

Answer 10

Yes, now find the square root of 98.

Answer 11

It comes out uneven, at 9.8 I assume you'd round it up to 10?

Answer 12

Yes, that's what I was assuming also..

Answer 13

Hmm, it says 10 was wrong. I guess they wanted it to be rounded down.

Answer 14

wow did they really say ten!!!

Answer 15

no, they wanted you to day "none of these"

Answer 16

because \(98\neq 100\) and so \(\sqrt{98}\neq 10\)

Answer 17

Ah, yeah that makes sense now actually.

Answer 18

Ohhh..

Answer 19

The question could've been more specific..like 'don't round your answer'

Answer 20

Now you know that you're not supposed to round..lol

Answer 21

Yeah they're not very good at that stuff lol. I'll just redo it later.

Answer 22

i hope no one thinks that 98 = 100
if you do, lend me $100 today, i will pay you back $98 tomorrow and we can call it even

Answer 23

Cool, you're a master :P

Answer 24

Yes, we know..lol. @satellite73

Answer 25

It's just that, I'm used to rounding :P