Question

A complex number, (a + bi), multiplied by (2 + 3i) and added to -i gives the product of (-11 + 5i) and (1 – i).

Answer 1

A=? b-?

Answer 2

@undeadknight26

Answer 3

@Preetha

Answer 4

@Kainui

Answer 5

@hero

Answer 6

@mathhasproblems

Answer 7

@SolomonZelman

Answer 8

@jabez177 @Jadeishere

Answer 9

I don't remember how to do this, I'm sorry, if I did I would be more than willing to help you

Answer 10

Thank you.

Answer 11

(a + bi) * (2 + 3i) -i = (-11 + 5i) * (1 – i)

2a + 3 ai + 2bi + 3bi^2 - i = -11 + 11i + 5i - 5 i ^2

Answer 12

now we are doing to do sums

Answer 13

then take all the imaginary numbers together and the others together.

Answer 14

2a - 3b = -11 +5
3 ai + 2 bi - i = 11i + 5i

Answer 15

Review after me.

Answer 16

2 a - 3 b = -6
3 a + 2b = 15

Answer 17

2a - 3 b = -6 * 2
3 a + 2b = 15 *-3

Answer 18

4a - 6b = -12
-9a + 6b = -45

Answer 19

I think i miscalculated something

Answer 20

or the number isn't cool at all.

Answer 21

Haha

Answer 22

That's why I hate PCs. Give me a minute gonna do it on a paper.

Answer 23

a = 3 b = 4

Answer 24

2 a - 3 b = -6 the first EQN
3 a + 2 b = 17 the second EQN