You put $1000 in a savings account which earns compound interest at a rate of 0.1% per month. If you don't make any deposits or withdrawls, how much will you have in your account in 3 years (36 months)? Round your answer to the nearest whole cent. A. $1036.64 B. $1331.00 C. $1003.00 D. $1430.08 @Daniellelovee
What does your book tell you about the compound interest? The probably gave you the formula right
\[Future~Value = Present~Value*(1 + rate)^{periods}\]
Simple interest formula
In 36 compounding periods, the value will become... 1000(1.001)^(36)
A = 1000(1 + (0.001 × 3))=?
This is compounding interest Daniell
just listen to him @Tallan
but how do you know that it is compound interest and not simple interest formula?
For each compounding period, the value of the account increases by 0.1%. That is the same as multiplying the value by 1.001. If you do that 36 times you get 1000*(1.001)(1.001)(1.001)......36times or Value = 1000(1.001)^(36)
You read the problem "...savings account which earns compound interest.."
*facepalm*
\[Future~ Value= $1000*(1.001)^{36} \approx\]
would it be A?
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