A helicopter's position is y(t)=A(t)^(3). A is a constant. T=0 when the helicopter leaves the ground.The helicopter drops its crate when it reaches a height of h =15 m. 2.5 second pass when it reaches the ground. How do I calculate A?

Question

A helicopter's position is y(t)=A(t)^(3). A is a  constant. T=0 when the helicopter leaves the ground.The helicopter drops its crate when it reaches a height of h =15 m. 2.5 second pass when it reaches the ground. How do I calculate A?

anonymous · Answer

2.5 seconds pass from the time the crate leaves the helicopter at 15 m high.

anonymous · Answer

*the moment crate dropped its velocity = helicopter velocity 
*helicopter velocity is the derivative of the position   v(t)=3A(t)^2
* finding crate velocity

anonymous · Answer

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