A right triangle has base (x - 6) units and height (6x - 12) units.
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OpenStudy (anonymous):
Part A: What is the square of the length of the hypotenuse of the triangle? Show your work.
Part B: What is the area of the triangle?
Part C: Using the solution obtained in Part B, explain the closure property of multiplication of polynomials.
OpenStudy (anonymous):
Only answer A through messages please :D
OpenStudy (alexandervonhumboldt2):
area: (6x-12)*(x-6)/2
OpenStudy (anonymous):
mhm....
OpenStudy (anonymous):
I can see you got that by multiplying (x - 6) by (6x - 12) right?
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OpenStudy (alexandervonhumboldt2):
yeah
OpenStudy (anonymous):
ok, what next?
OpenStudy (alexandervonhumboldt2):
and then divde by 2
OpenStudy (tylerd):
1/2 base times height = right triangle area
OpenStudy (anonymous):
yeah.... oh thanks :D
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OpenStudy (alexandervonhumboldt2):
1/2*b*h is the area of any triangle
OpenStudy (anonymous):
x=3x^2−24x+36 right?
OpenStudy (anonymous):
(refresh page)
OpenStudy (alexandervonhumboldt2):
hypotenuse^2=(x-6)^2+(6x-12)^2
OpenStudy (anonymous):
what is the hypotenuse?
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OpenStudy (tylerd):
hero formula is the area of any triangle
OpenStudy (anonymous):
what is the hypotenuse in your case AlexandervonHumboldt2?
OpenStudy (alexandervonhumboldt2):
hypotenuse^2=(x-6)^2+(6x-12)^2
OpenStudy (alexandervonhumboldt2):
hypotenuse=sqrt((x-6)^2+(6x-12)^2)
OpenStudy (anonymous):
after trying multiple times, I don't believe it's possible to solve that without knowing what x is @AlexandervonHumboldt2 !
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OpenStudy (alexandervonhumboldt2):
it cannot be known
OpenStudy (alexandervonhumboldt2):
the answer is with variable
OpenStudy (anonymous):
ah ok.... so mind helping me out?
OpenStudy (alexandervonhumboldt2):
ok
OpenStudy (anonymous):
:)
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OpenStudy (anonymous):
so what do we start by doing?
OpenStudy (alexandervonhumboldt2):
what you need help with?
OpenStudy (anonymous):
solving for the hypotenuse :|
OpenStudy (alexandervonhumboldt2):
ok
OpenStudy (anonymous):
so what do we start by doing?
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OpenStudy (alexandervonhumboldt2):
so in part A we need the sqruare of hypotenuse so...
OpenStudy (alexandervonhumboldt2):
hypotenuse^2=(x-6)^2+(6x-12)^2
OpenStudy (anonymous):
ok...
OpenStudy (alexandervonhumboldt2):
x^2-12x+36+36x^2-144x+144
OpenStudy (anonymous):
37x^2+−156x+180
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OpenStudy (alexandervonhumboldt2):
37x^2-156x+180
OpenStudy (alexandervonhumboldt2):
yes
OpenStudy (anonymous):
is that the hyp or still more to do?
OpenStudy (alexandervonhumboldt2):
square of hypotenuse is 37x^2-156x+180
OpenStudy (anonymous):
ah ok... so A?
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OpenStudy (alexandervonhumboldt2):
yeah
OpenStudy (anonymous):
off to b?
OpenStudy (alexandervonhumboldt2):
area: (6x-12)*(x-6)/2
OpenStudy (anonymous):
haha ok then, off to c?
OpenStudy (alexandervonhumboldt2):
(6x-12)*(x-6)/2=(6x^2-48x+72)/2=3x^2-24x+36
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OpenStudy (anonymous):
ok wow that is a lot of calculating :D
OpenStudy (alexandervonhumboldt2):
not a lot had you fanned me?
OpenStudy (alexandervonhumboldt2):
thx now
OpenStudy (anonymous):
Haha yw :D
OpenStudy (anonymous):
Can you through messages help me explain the closure property?
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OpenStudy (alexandervonhumboldt2):
probably no because i dont know closure property
OpenStudy (alexandervonhumboldt2):
sorry
OpenStudy (anonymous):
no that's ok, but do you know anyone who does?
OpenStudy (alexandervonhumboldt2):
@ganeshie8
OpenStudy (alexandervonhumboldt2):
@Directrix
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OpenStudy (alexandervonhumboldt2):
@TylerD
OpenStudy (anonymous):
thanks :D
OpenStudy (alexandervonhumboldt2):
i mesagged ganishe lets see
OpenStudy (anonymous):
ok :)
OpenStudy (tylerd):
?
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OpenStudy (anonymous):
hi :D
OpenStudy (tylerd):
oh closure property
OpenStudy (anonymous):
yeah :D
OpenStudy (alexandervonhumboldt2):
i found explanation: A set has closure under an operation if performance of that operation on members of the set always produces a member of the same set; in this case we also say that the set is closed under the operation.
OpenStudy (anonymous):
hmm... somewhat complicated, but I understand some parts...
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OpenStudy (alexandervonhumboldt2):
A set that is closed under an operation or collection of operations is said to satisfy a closure property.
OpenStudy (anonymous):
how would we explain that using b?
OpenStudy (alexandervonhumboldt2):
probably as b has no limits
OpenStudy (anonymous):
oh really... why?
OpenStudy (tylerd):
no clue
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OpenStudy (alexandervonhumboldt2):
well because in ^2 everything is poitie
lenght cannot be negative
OpenStudy (anonymous):
ah ok...
OpenStudy (anonymous):
thanks a lot.... :D
OpenStudy (alexandervonhumboldt2):
np
OpenStudy (alexandervonhumboldt2):
i had becomed green today
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OpenStudy (tylerd):
its probably something dumb like hieght/2 times base/2 = blah
OpenStudy (alexandervonhumboldt2):
haha
OpenStudy (anonymous):
oh and congrats @AlexandervonHumboldt2 ... I can see, you're green not lime :D
OpenStudy (alexandervonhumboldt2):
well yeah thx
OpenStudy (alexandervonhumboldt2):
i posted that in study group OpensTudy feedback
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