Question

Solve on the interval [0, 2pi): 3sec(x-1)=2

Answer 1

hmm this concerns the entire circle. If I remember correctly we need the trig function by itself.

Answer 2

and then when we get secx = 1 that's actually 1/cosx = 1. so cosx = 1/1 => cosx = 1... then we need to find out what radian value actually does produce this in cos x land... and supposedly once we find that, we can subtract that by 2pi. It's been years since I've done this, but that's how the method goes ... I think

Answer 3

I see cos 60 cos 120 and cos 30 one of these guys have to make a 1 somehow... hmmm?

Answer 4

OH GEEZ we need to take the cos^-1(x) for 1

Answer 5

and apparently cos^-1(1) is 0... that's not what I need

Answer 6

so maybe I need sec^-1(1)

Answer 7

so after we take the inverse of 1 which is what angle we need that can produce a value of 1 , we have pi/3

Answer 8

so now we need to subtract 2pi with pi/3 for our other angle