when heated, KCIO3 decomposes into KCI and o2. If this reaction produced 14.5 grams of KCI, how much O2 was produced (in grams)? I know that I have to balance the equation first... 2KClO3----> 2KCl+3O2 but I don't really know the rest. I know how to convert from moles to grams, but this problem confused me..... any help would be appreciated.
Are you trying to find the mass of the O2 produced?
If yes let me know to answer your question.
I'm not sure, it says how much O2 was produced (in grams)?.
@korosh23
OK.
First you transfer the grams of KCl to moles of KCl. Then you you use Molar bridge which is using the balanced equation.
Now you have the moles of O2. By the mole birdge.
Simply change moles of O2 to grams of O2 by using molar mass on the periodic table. Be careful, O2 is 32.0 g not 16.0. Additionally, O2 is diatomic element. Remember HOFBrINCl.
Let me know if you needed more help.
i still don't know how to do it till the end.. that's what I got so far.. (14.5g)(1mole/.197)(3mole/1mole) = that should give me the number of moles in O2 I got a .177619moles of O2 >>> do I just convert to grams now?
@korosh23
Yes you have to convert in grams now.
If its possible please give a medal. Thank you.
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