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Geometry 21 Online
OpenStudy (anonymous):

Which is closest to the total area in square feet of the foundaton? (diagram in question))

OpenStudy (anonymous):

OpenStudy (anonymous):

What exactly is your question? Are you asking for the total area of the foundation?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Okay so you got your area of the smallest square. To get the area of the larger square you need the diameter of the semi-circle

OpenStudy (anonymous):

yeah and yeah i know. is te diameter 20?

OpenStudy (anonymous):

What exactly is the 40ft, the circumference?

OpenStudy (anonymous):

yeah i think

OpenStudy (anonymous):

You think? Does it tell you in the question?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Okay so assuming 40ft is the length of the curvy part you can do.. \[\frac{ 2(40) }{ \pi } = d\] to get the diameter.

OpenStudy (anonymous):

its 20

OpenStudy (anonymous):

what is 20...?

OpenStudy (anonymous):

40 divided by 2

OpenStudy (anonymous):

No...40 is your length of the curvy side multiply that by 2 to get the circumference and divide it by pi to get your diameter.

OpenStudy (anonymous):

Then use the diameter to get area of the rectangle And to get the area of the semi-circle...use \[A = \frac{ 1 }{ 2 } \pi \times \left\{ \frac{ d }{ 2 }\right\}^{2}\]

OpenStudy (anonymous):

im confused

OpenStudy (korosh23):

Find the area of the smaller and big rectangle. Add them up. Next find the area of the circle and then divide it by 2. In that case you get the area of half of the circle. At the end, add the area of circle with the areas of the rectangles.

OpenStudy (anonymous):

i cant find the area for the big rectangle

OpenStudy (anonymous):

@korosh23

OpenStudy (danjs):

The circumference is found by \[C = 2\pi*r\] They gave you half of the circumference, is 40 ft\[\frac{ 1 }{ 2 }C = \pi*r = 40~ft\] The radius of the circle is \[r = \frac{ 40 ~ft }{ \pi }\]

OpenStudy (danjs):

The diameter is double that , and is also the length of the side of the Larger Box.

OpenStudy (danjs):

Small box Area = 25 x 16 + large box area = 32.5 x 80/pi + Area of Semi-Circle = \[\frac{ \pi*[40/\pi]^2 }{ 2 }\]

OpenStudy (anonymous):

i cant figure out the answer though im confused

OpenStudy (anonymous):

@DanJS

OpenStudy (anonymous):

Well that the I am assuming that 40 is half a circumference of a circle I doubled that half circumference into 80 then I just plugged it into the formula for getting a circumference and I worked backwards 80= 2*3.14*r I got the 6.28 and then divided 80 by 6.28 getting 12.7388... So that would be your radius of a circle with the circumference of 80 or in your case a half circle. Now that you have your radius just calculate the area of a full circle then divide it by 2 to get the area of your little half circle and to get the missing measurement of that other box just double the radius.

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