Which is closest to the total area in square feet of the foundaton? (diagram in question))
2328
how'd you get that answer?
@k.rajabhishek
\[c=2 \pi r,\pi r=40,r=\frac{ 40 }{ \pi }\] \[area=25*16+32.5*\frac{ 80 }{ \pi }+\frac{ \pi \left( \frac{ 40 }{ \pi } \right)^2 }{ 2 }\] calculate it.
\[area=400+\frac{ 2600 }{ \pi }+\frac{ 800 }{ \pi }=400+\frac{ 3400 }{ \pi }=?\]
can you explain it because im confused. @surjithayer
in order to get the length of the 2nd rectangle, you need to find the diameter of the semicircle on the right.
length=diameter=2*radius \[=2*\frac{ 40 }{ \pi }=\frac{ 80 }{ \pi }\] circumference of circle\[=2 \pi r\] circumference of semi circle\[=\frac{ 2~\pi~r }{ 2 }=\pi~r\]
now any problem.
i cant figure out the area of the semi circle
you have to find the diameter first since it is a semicircle then we can find the diameter by using pi*d=80 (40 x 2=80) d=80/pi
so 80^2 x 3.14?
80/pi=diameter so radius=40/pi now we plug that into the equation A=(pi x r^2)/2 since it is a semicircle
so the area of the semicircle would be |dw:1422811253194:dw|
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