Please help with a related rates problem! Will fan and medal!
A rotating beacon is located 2 miles out in the water. Let A be the point on the shore that is closest to the beacon. As the beacon rotates at 10 revolutions per minute, the beam sweeps down the shore once each time it revolves. Assume that the shore is straight. How fast is the point where the beam hits the shore moving at an instant when the beam is lighting up a point 2 miles downshore from point A?
So far, I know that there is a triangle with angle theta at the beacon/lighthouse and that, because of the circle of its revolutions, dtheta/dt= 20pi
Also, because it is asking for the instantaneous speed at x=2miles (for side x on this triangle) I am solving for dx/dt
Do you have a drawing set up?
@jim_thompson5910 Thank you very much, but I just got it all figured out!
ok great, I'm glad you did
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