Mathematics
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OpenStudy (anonymous):
Subtracting Fractions:
12-3/4=
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OpenStudy (kohai):
So for this one, you WILL have to make 12 an improper fraction
OpenStudy (anonymous):
12 over 1
OpenStudy (anonymous):
|dw:1422855530427:dw|
OpenStudy (kohai):
No that's still a fraction. I guess you don't HAVE to, but... okay, what's 1- 3/4? Or, 100-75? etc
OpenStudy (kohai):
Oh I guess you could do that. Then make them like denominators
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OpenStudy (jhannybean):
Find the LCM between 1 and 4. What is that?
OpenStudy (anonymous):
4
OpenStudy (jhannybean):
Ok, so multiply the numerator and denominator \(\dfrac{12}{1}\) by 4.
OpenStudy (jhannybean):
What do you get (as a fraction)?
OpenStudy (anonymous):
and the second number is 3/4?
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OpenStudy (jhannybean):
Yeah, but what do you get for the first one?
OpenStudy (nurali):
\[\frac{ 12 }{ 1 }-\frac{ 3}{ 4 }\]
OpenStudy (nurali):
LCM
OpenStudy (jhannybean):
\[\frac{12}{1} \cdot \frac{4}{4}\]
OpenStudy (nurali):
\[\frac{ 12*4-3*1 }{ 1*4 }\]
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OpenStudy (anonymous):
It is 4 so then..
OpenStudy (jhannybean):
Once you get that answer, combine the two fractions as @Nurali did, and simplify.
OpenStudy (nurali):
\[\frac{ 48-3 }{ 4 }\]
OpenStudy (nurali):
\[\frac{ 45 }{ 4 }\]
OpenStudy (jhannybean):
So \(12 \cdot 4\) = 48.
You have 3 ontop the other fraction.
Subtract the numerators, 48- 3
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OpenStudy (jhannybean):
put it over 4.
OpenStudy (anonymous):
Ok so wait.. i got confused now..