Question

caculate the value of of (oh-) from the given (H30+) and label the solution as acidic or basic.

a. 10^-8 M
________*10_____^ M

b. 10^-11 M
______*10^ M

Answer 1

\(\sf pH= -log [H^+]\\pOH= 14-pH\)

Answer 2

can you also explain to me how i would type this in a calucator

Answer 3

I have TI 30 calculator

Answer 4

\(\sf [OH^-] = 10^{-pOH}\)

Answer 5

not sure about your calculator..

but type "-" then "log" , enter the values from above, then say okay.
that will be your pH...

Answer 6

i dont know how to do 10^-8 on calculator

Answer 7

do you know

Answer 8

can you take a pic of your calculator ?

it's either "EXP" or "x10^n", depending on your calc.

Answer 9

is it -8

Answer 10

the anwere

Answer 11

yes for pH, but you are looking for OH-, so subtract the value that you get from 14

Answer 12

6

Answer 13

right

Answer 14

yes! that will be the pOH
last step would be \(\sf 10^ 6\), this will be your OH

Answer 15

SO IT IS -8 *10^6 M

Answer 16

or 8 *10^ 6 M

Answer 17

nope, 10^6 is the answer already.

you used pH=8 to solve pOH= 14-8 = 6

then you use pOH to solve for OH

Answer 18

how would i do that

Answer 19

can you please explain

Answer 20

8 *10^ 6 M

Answer 21

so this is the anwer then for the question right

Answer 22

1000000

Answer 23

okay i'll do it step by step for you.

"calculate the value of of (oh-) from the given (H30+) "

Unknown: [OH-]
Known: [H+]

Analysis/Steps:

1. \(\sf pH= -log [H^+]\) -> use this to calculate for the pH since [H+] is given.

\(\sf pH= -log [H^+]= - log [10^{-8}]= 8\) , so remember pH = 8

2. \(\sf pOH= 14-pH\) -> use this to calculate for pOH

\(\sf pOH= 14-pH= 14-8=6\), therefore pOH is 6

3. \(\sf [OH^-] = 10^{-pOH}\) use this to calculate for your unknown.
\(\sf [OH^-] = 10^{-pOH}=10^{-6}\)

therefore your answer will be \(\sf [OH^-] = 10^{-6}\)

Answer 24

now follow this steps with the second problem

Answer 25

\(\sf [OH^-] = 10^{-6}\ or\ 1 \times 10 ^{-6} M\)

Answer 26

now would it be acid or basic

Answer 27

if pH > 7 , the solution will be basic
if pH = 7 , it will be neutral
if pH < 7, it will be acidic

so look at the value of the pH , we calculated and you tell me if its acidic or basic

Answer 28

are you sure? what's the value of our pH?

Answer 29

basic

Answer 30

PH is 8

Answer 31

right (:

can you try doing the second one? I'll check if it's right

Answer 32

is it 1* 10^-3

Answer 33

i tried on my own

Answer 34

yes! glad you got it ^_^
so will it be acidic or basic?

Answer 35

basic as PH IS 11

Answer 36

RIGHT

Answer 37

yEp! !!

Answer 38

do you understand it now?

Answer 39

YES THANKS

Answer 40

no prob! :)