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Mathematics 19 Online
OpenStudy (anonymous):

Find the inverse of the function f(x)=mx+b.

OpenStudy (freckles):

can you solve y=mx+b for x ?

OpenStudy (freckles):

are you there?

OpenStudy (anonymous):

I think I have the answer.

OpenStudy (freckles):

oh okay do you want to post it

OpenStudy (anonymous):

y= -bm(1+m) / (m^2-1) + b

OpenStudy (freckles):

Hmm... solving y=mx+b should only be a two step process Shouldn't result in all of that

OpenStudy (freckles):

Solving y=mx+b for x: 1st step: Subtract b on both sides 2nd Step: Divide both sides by m (of course we are assuming m isn't 0 you know since we can't divide by 0)

OpenStudy (anonymous):

y = (x-b) / m

OpenStudy (freckles):

right y=mx+b step 1: we have y-b=mx step 2: we have (y-b)/m=x interchanging x and y gives y=(x-b)/m

OpenStudy (anonymous):

so I would get that for my final answer

OpenStudy (freckles):

the inverse is what we have found above

OpenStudy (freckles):

If you aren't sure you test it

OpenStudy (anonymous):

thank you.

OpenStudy (freckles):

f(x)=mx+b and g(x)=(x-b)/m check by making sure you get x for both of g(f(x)) and f(g(x)) \[f(g(x))=x \text{ and } g(f(x))=x\]

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