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Mathematics 15 Online
OpenStudy (anonymous):

verify each identity

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

OpenStudy (anonymous):

its number 60

OpenStudy (anonymous):

@campbell_st

OpenStudy (anonymous):

@freckles

OpenStudy (anonymous):

@Hero

Directrix (directrix):

Giving up on me, I see. lol

OpenStudy (anonymous):

oh sorry i thought you left

OpenStudy (anonymous):

or logged off or something, but no never lol

Directrix (directrix):

When I opened the attachment, the browser crashed.

Directrix (directrix):

Let the others help. It's okay.

OpenStudy (anonymous):

no problem, can you look at it still?

OpenStudy (anonymous):

they dont really respond and i need help fast

Directrix (directrix):

For the right side, I have a working change from what it was to this (1 - cosx)/ 2. Now, what to do with the left side. What is sin^2 (x/2) =

OpenStudy (anonymous):

we can change the csc to 1/sinx

Directrix (directrix):

Isn't the left side also 1 - cosx all over 2 when you square the formula for sin (x/2)

OpenStudy (anonymous):

yes

Directrix (directrix):

Do you see how to get the right side to be (1 - cosx) all over 2?

OpenStudy (anonymous):

would it just be \[\frac{ 1-\cos^2x }{ 2 }\]

Directrix (directrix):

|dw:1423011740300:dw|

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