Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

verify each identity

OpenStudy (anonymous):

OpenStudy (anonymous):

did you get it

OpenStudy (anonymous):

its number 66

OpenStudy (kainui):

Show us your best attempt at trying to show it's true.

Directrix (directrix):

Do you have a formula in the book for cot(x/2)

OpenStudy (anonymous):

no i dont, that's what's confusing me i dont know where to start

Directrix (directrix):

What is the reciprocal function of cotangent?

OpenStudy (anonymous):

cos

Directrix (directrix):

No. Look at the attached chart.

Directrix (directrix):

What is the reciprocal function of cotangent?

OpenStudy (anonymous):

tan

OpenStudy (anonymous):

\[\sqrt{\frac{ 1-\cos \alpha }{ 1+\cos \alpha }}\]

Directrix (directrix):

What did you just post? Half angle for tangent or cotangent?

OpenStudy (anonymous):

half angle for tangent

Directrix (directrix):

Because the tangent and cotangent are reciprocals, I would like to think that the cotangent of the half angle is the reciprocal of the expression you entered.

OpenStudy (anonymous):

\[\sqrt{\frac{ 1+ \cos \alpha }{ 1-\cos}}\]

Directrix (directrix):

Let's aim for that. I think it can be rewritten in a simpler way.

OpenStudy (anonymous):

how should i go about simplifying it?

Directrix (directrix):

Try rationalizing the denominator

OpenStudy (anonymous):

\[\sqrt{\frac{ 1+\cos \alpha }{ 1-\cos \alpha }} (\frac{ 1-\cos \alpha }{ 1-\cos \alpha})\]

Directrix (directrix):

Radical symbol

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

with the symbol

Directrix (directrix):

Did you get this far? (see attachment) I break up my square roots of a quotient to be the quotient of the square roots.

Directrix (directrix):

Multiply out the numerators and post what you get.

OpenStudy (anonymous):

okay one moment

OpenStudy (anonymous):

Directrix (directrix):

Incorrect move. One of those is a radical. The other is not. And, you cannot divide them out. |dw:1423016957879:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!