Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[2y ^{2}x - y ^{2} - (1+ 3y) = x\]
OpenStudy (nikato):
Subtract 2y^2 x on both sides
OpenStudy (nikato):
Factor out the x.
So the right side becomes
x(1-2y^2)
OpenStudy (nikato):
Finally divide both sides by
1-2y^2.
And you have solve x in terms of y
OpenStudy (anonymous):
so it should look like this *hold on
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[y^2 - (1 +3y)/1-2y^2\]
OpenStudy (anonymous):
\[\frac{ y^2-(1+3y) }{ 1-2y^2 }\]
OpenStudy (nikato):
*-y^2
Don't forget the negative sign.
And if you were to write it the first way, remember to put in the paranthese/brackets or else you would have wrote a completely different equation
OpenStudy (anonymous):
oh okay but its correct except for the negative
OpenStudy (nikato):
Yea
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
okay so what is the next step?
OpenStudy (nikato):
That's it!
That would be your answer
OpenStudy (anonymous):
oh wow okay lol can you help me on another?
OpenStudy (nikato):
Sorry I've got to go now.
But I'll be back later if you still need help