Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

Solve for x in terms of y

OpenStudy (anonymous):

\[2y ^{2}x - y ^{2} - (1+ 3y) = x\]

OpenStudy (nikato):

Subtract 2y^2 x on both sides

OpenStudy (nikato):

Factor out the x. So the right side becomes x(1-2y^2)

OpenStudy (nikato):

Finally divide both sides by 1-2y^2. And you have solve x in terms of y

OpenStudy (anonymous):

so it should look like this *hold on

OpenStudy (anonymous):

\[y^2 - (1 +3y)/1-2y^2\]

OpenStudy (anonymous):

\[\frac{ y^2-(1+3y) }{ 1-2y^2 }\]

OpenStudy (nikato):

*-y^2 Don't forget the negative sign. And if you were to write it the first way, remember to put in the paranthese/brackets or else you would have wrote a completely different equation

OpenStudy (anonymous):

oh okay but its correct except for the negative

OpenStudy (nikato):

Yea

OpenStudy (anonymous):

okay so what is the next step?

OpenStudy (nikato):

That's it! That would be your answer

OpenStudy (anonymous):

oh wow okay lol can you help me on another?

OpenStudy (nikato):

Sorry I've got to go now. But I'll be back later if you still need help

OpenStudy (anonymous):

okay thank you.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!