Solve for x in terms of y
\[2y ^{2}x - y ^{2} - (1+ 3y) = x\]
Subtract 2y^2 x on both sides
Factor out the x. So the right side becomes x(1-2y^2)
Finally divide both sides by 1-2y^2. And you have solve x in terms of y
so it should look like this *hold on
\[y^2 - (1 +3y)/1-2y^2\]
\[\frac{ y^2-(1+3y) }{ 1-2y^2 }\]
*-y^2 Don't forget the negative sign. And if you were to write it the first way, remember to put in the paranthese/brackets or else you would have wrote a completely different equation
oh okay but its correct except for the negative
Yea
okay so what is the next step?
That's it! That would be your answer
oh wow okay lol can you help me on another?
Sorry I've got to go now. But I'll be back later if you still need help
okay thank you.
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