Question

The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).

y = 2x + 16
y = negative 1 over 2x + 17 over 2
y = − 1 over 2x + 7 over 2
y = 2x − 4

Answer 1

The equation of line QR is y = negative 1 over 2x + 1. Write an equation of a line perpendicular to line QR in slope-intercept form that contains point (5, 6).

I assume the equation is y = (-1/2)x + 1. This equation is in the standard slope-intercept form:

y = mx + b

Where m is the slope of the line and b is the y-intercept. In your equation, m = -1/2 and b= 1.

The slope of a line perpendicular to line QR will have a slope of -(1/m) = -1/(-1/2) = 2. So the equation of the line perpendicular to line QR is:

y = 2x + b

To find b, insert the point (5,6) that the line contains as defined in the problem statement and solve for b:

y = 2x + b
6 = 2(5) + b [Insert x=5, y=6]
6 = 10 + b
-4 = b [Subtract 10 from both sides

So the final equation for the line perpendicular to line QR is:

y = 2x - 4

Answer 2

Ohh! Okay than you so much! :)