Question

write as a single fraction. simplify.

-8b-3y/ 8b + 5b+2y/ 2b +1

Answer 1

@iGreen.

Answer 2

Is this it?

\(\dfrac{-8b-3y}{8b} + \dfrac{5b+2y}{2b+1}\)

Answer 3

the negative in front of the 8b is in front of the entire equation and the +1 is seperate

Answer 4

Oh, so it's this:

\(-\dfrac{8b-3y}{8b} + \dfrac{5b + 2y}{2b} + 1\)

Answer 5

yes =)

Answer 6

@Luigi0210

Answer 7

Ohh this is a toughiee

Answer 8

Okay, so to do this you have to get common denominators. Do you know how to do that?

Answer 9

would it be four?

Answer 10

oh wait I accidentally posted this twice hold on

Answer 11

Actually the common factors would be 8b, so just multiply the second by 4 to get 8b, and the 1 will be 8b/8b, like so:

\(\LARGE -\frac{8b-3y}{8b} +\frac{5b+2y}{2b} (4) + \frac{8b}{8b} \)

Simplify:

\(\LARGE -\frac{8b-3y}{8b} +\frac{20b+8y}{8b} + \frac{8b}{8b} \)

Now get it all over a common denominator like so:

\(\LARGE \frac{(20b-8b)+(8y+3y)+(8b)}{8b}\)
I also distributed the negative out

So it'll just be \(\LARGE \frac{20b+11y}{8b}\)

Make sense?

Answer 12

yes =)