Question

FAN AND MEDAL!!

How many grams of potassium chloride must decompose to produce 69.9 milliliters of potassium metal, if the density of potassium is 1.78 g/mL? Show all steps of your calculation as well as the final answer.

KCl → K + Cl2

Answer 1

@paki

Answer 2

1/

2KCl → 2K + Cl2

one molecule of KCl will give one molecule of K so their amounts are equal

n(KCl) = n(K) , n(K) = m(K)/M(K), m(K) = r(density) * V

so n(K) = (r(density) * V)/M(K)

m(KCl) = n(KCl) * M(KCl)

m(KCl) = [(r(density) * V)/M(K)] * M(KCl)


m(KCl) = [ (69.9 mL * 1.78g/mL)/39 g/ mol] * 74.55 g mol−1

m(KCl) = 237.83 g

Answer 3

hopefully that helps

Answer 4

Wow! Thank you so much man! The final answer is m(KCl) = 237.83 g??

Answer 5

yes it is and your welcome. Plus im a girl

Answer 6

Lol I call everyone man

Answer 7

@nacholover

Answer 8

oh ok.But your welcome anything else i can help you with.

Answer 9

Yes gimme a few moments I have 2 more chem questions!! @nacholover

Answer 10

k just tag me in the post so i can answer them