Question

Help please. @iGreen. @hartnn @AnswerMyQuestions @Legends

Answer 1

Variable y varies directly with x^2, and y = 72 when x = 6.

What is the value of y when x = 4?

Y = ___

Answer 2

\(y = kx^2\)

Plug in what we know:

\(72 = k(6)^2\)

Simplify the exponent:

\(72 = 36k\)

Divide 36 to both sides:

\(k = 2\)

Now we now that the constant is 2, we can plug this in with x = 4:

\(y = kx^2\)

\(y = (2)(4)^2\)

Simplify and you get 'y'.

Answer 3

one sec. brb. moms calling

Answer 4

Kk

Answer 5

back

Answer 6

4^2 = 16

Answer 7

2 x 16 = 32

Answer 8

32 = answer?

Answer 9

Yep

Answer 10

You got it.

Answer 11

thanks :)

Answer 12

No problem.

Answer 13

gonna tag you to another one