Two forces with magnitudes of 150 and 75 act on an object at angles of 30 degrees and 150 degrees respectively. Find the direction and magnitude of the resultant force. Work shown below but I am getting stuck.

Question

sleepyjess · Answer

$\sf y_1=75*.5*sqrt3\y_1=64.95\x_1=75*.5\x_1=37.5\y_2=150*.5*sqrt3\y_2=129.9\x_2=150.5\x_2=75$

sleepyjess · Answer

@ganeshie8

sleepyjess · Answer

@StudyGurl14

sleepyjess · Answer

@e.mccormick

e.mccormick · Answer

Well, I would use vector addition... but I am not sure which methods of doing so you have studied.

e.mccormick · Answer

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sleepyjess · Answer

Here is what my teacher said, but I don't really get it. Components of first vector: 150 Components of second vector: 75 Then add the two together to find the resultant vector.

e.mccormick · Answer

The 150 and 75 outside the vectors are the magnitudes.  The vectors are being represented in $M\langle\cos\theta,\sin \theta \rangle$ notation.

e.mccormick · Answer

Let's look at another diagram real quick.
|dw:1423162301820:dw|
Say I have that random vector.

e.mccormick · Answer

The length or radius it would sweep is the Magnitude.
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