Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@FibonacciChick666
OpenStudy (anonymous):
@Nnesha
OpenStudy (anonymous):
@AnswerMyQuestions
OpenStudy (anonymous):
HELP PLZZZZZZZZZ
OpenStudy (fibonaccichick666):
do you mean convert those numbers to binomial form?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes I think its one of these 2011, 0, 2012, or 1
OpenStudy (anonymous):
im not sure though.. but do u know how to do this
OpenStudy (anonymous):
@DuckDynastyfan923
OpenStudy (anonymous):
the answers are A. 2011
OpenStudy (anonymous):
B. 0
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
C. 2012
OpenStudy (anonymous):
D. 1
OpenStudy (anonymous):
Also no its just says "find the binomail coefficient: (2012)
(2011)
OpenStudy (anonymous):
@Abhisar
OpenStudy (anonymous):
how r u working it
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@Legends
OpenStudy (anonymous):
so?
OpenStudy (anonymous):
should i get us help
OpenStudy (anonymous):
HELLPPPPp
OpenStudy (anonymous):
HELPPPPPPPPPP USSSSSS
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mathmate):
Do you mean: \[\left(\begin{matrix}2012 \\ 2011\end{matrix}\right)\] ?
OpenStudy (anonymous):
yes
OpenStudy (mathmate):
A binomial coefficient
\(\left(\begin{matrix}n \\ r\end{matrix}\right)\)
is defined as
\(\dfrac{n!}{(n-r)!r!}\)
So substitute the numbers and find your answer.
OpenStudy (anonymous):
yes but after that wat
OpenStudy (anonymous):
i can do that its just i dont know what to do after
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mathmate):
You will need to substitute n=2012, r=2011, and calculate your answer, choose from the choices.
OpenStudy (anonymous):
ok so D then considering they be nothing i else i tihnk
OpenStudy (anonymous):
im thinking d
OpenStudy (anonymous):
cant be 2011 or 2012
OpenStudy (mathmate):
It's ok with me if you decide to guess and not calculate!
Still Need Help?
Join the QuestionCove community and study together with friends!