A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 C/m? Show all of the work needed to solve this problem.

I need to know what formulas I use for Colligative properties.

Question

A solution is made by dissolving 10.20 grams of glucose (C6H12O6) in 355 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 C/m? Show all of the work needed to solve this problem.

I need to know what formulas I use for Colligative properties.

anonymous · Answer

@Australopithecus

australopithecus · Answer

http://chemwiki.ucdavis.edu/Physical_Chemistry/Physical_Properties_of_Matter/Solutions_and_Mixtures/Colligative_Properties/Freezing_Point_Depression

australopithecus · Answer

This formula should work for this problem

australopithecus · Answer

If you dont know molality = moles of solute/kg of solvent

australopithecus · Answer

It is used when temperature is a variable because it is a concentration that is independent of temperature

anonymous · Answer

woot thanks