Question

check my answer please! will award a medal.

Answer 1

it is so simple i just want to make sure im not missing anything.

Answer 2

@jdoe0001 hey could you check this really quick?

Answer 3

that's correct

Answer 4

okay great. thank you!

Answer 5

hmm hold the mayo

Answer 6

ah okay

Answer 7

the negative only would multiply the numerator
NOT the denominator

or the denominator, BUT not the numerator

Answer 8

hmmm

Answer 9

why is that?

Answer 10

could it be C then?

Answer 11

lemme do it quick

Answer 12

\(-f(a)\implies -\left(\cfrac{2a}{a-1}\right)\to
\begin{cases}
-\cfrac{2a}{a-1}\to \cfrac{-2a}{a-1}\\
-\cfrac{2a}{a-1}\to \cfrac{2a}{-(a-1)}\to \cfrac{2a}{-a+1}\to -\cfrac{2a}{a+1}
\end{cases}\)

Answer 13

ah okay, so it would be C. i see what you got. thank you!

Answer 14

it said it was incorrect..hmm

Answer 15

C?

Answer 16

yeah..i wonder why.

Answer 17

i may send it to my teacher and see if she can tell me why.

Answer 18

well... B or C fit the bill

as far as I can see it, -f(a) simply means -1 * f(a) or \(\bf \cfrac{-1}{1}\times \cfrac{2a}{a-1}\quad or\quad \cfrac{1}{-1}\times \cfrac{2a}{a-1}\)

Answer 19

yeah i got what you did when i solved it. i think i will ask her why it said it was incorrect.

Answer 20

k