Question

Do these systems have one solution, coincidental lines or infinite many solutions and why:
3x-y=0
6x-2y=3

Answer 1

Multiply this equation by 2 : 3x-y=0

Then, compare it to the second equation.

Answer 2

ok so 3 times 2 =6

Answer 3

and theres 6x in the second equation...do i have to multiply 1y by 2 as well? @Directrix

Answer 4

3x times 2 = ?

-y times 2 = ?

0 times 2 = ?

Answer 5

3x times 2=6x
-y times 2=-2y
0 times 2= 0

Answer 6

How does that compare to the second equation?

6x -2y = 0
6x -2y = 3
------------

Answer 7

that they have the same slope and y-int but a different b

Answer 8

does that make it no solution?

Answer 9

b is used for the y-intercept

Answer 10

6x -2y = 0
6x -2y = 3
------------

If you subtract one of these from the other, you get 0 = -3.

So, on the day that 0 = -3, the equations will have a solution.

Answer 11

And, the answer is ? @shelby1290

Answer 12

why and what do you subtract
its one solution

Answer 13

Addition/Subtraction, Substitution, and Graphing are 3 ways to find a common solution to a system of 2 equations.

So, I subtracted the second from the first one (after you multiplied it by 2) and arrived at something that could not be true.

The variables subtracted and disappeared, leaving 0 = -3 which cannot be.

No common solution was found.

Yes, the lines have the same slope and a different y-intercept.

Answer 14

>>>that they have the same slope and y-int but a different b
What you wrote is not correct.
The y-intercepts are different.

Answer 15

Kk I see. Thank you!!

Answer 16

@Directrix just to check, the final answer is no solution?

Answer 17

Correct, no solution @shelby1290

Answer 18

okay

Answer 19

do you have time for another one?

Answer 20

@Directrix ^

Answer 21

Close this thread and post the new question in a fresh thread.

Answer 22

okay