Mathematics
14 Online
OpenStudy (anonymous):
If (x + 2) is a factor of x3 − 6x2 + kx + 10 , k =
please help !
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OpenStudy (misty1212):
HI!!
OpenStudy (misty1212):
i have a suggestion!
OpenStudy (misty1212):
if \((x+2)\) is a factor, then if you replace \(x\) by \(-2\) you have to get zero
OpenStudy (misty1212):
put \(x=-2\) in to \(x^3+6x^2+kx+10=0\) and solve for \(k\)
OpenStudy (anonymous):
i thank that means put
\[(-2)^3+6(-2)^2-2k+10=0\] right?
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OpenStudy (misty1212):
that should do it
you good from there?
OpenStudy (anonymous):
Yeah I should be good from here , but would you mind checking my answer when I'm done ?
OpenStudy (misty1212):
no not at all go ahead and post it
OpenStudy (anonymous):
So I just did it and the answer I got is -11
OpenStudy (misty1212):
oops
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OpenStudy (misty1212):
\[-8+12-2k=10=0\] is a start
OpenStudy (anonymous):
Ok so I redid it and this time I got 2 as an answer
OpenStudy (misty1212):
yeah i made a mistake too
OpenStudy (misty1212):
first step is
\[-8+24-2k+10=0\]
OpenStudy (misty1212):
then \[26-2k=0\\
26=2k\\
13=k\]
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OpenStudy (anonymous):
Yeah I got 13 over here as well
OpenStudy (anonymous):
good!
OpenStudy (anonymous):
thankyou so much for the help :)
OpenStudy (misty1212):
\[\color\magenta\heartsuit\]